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Cape Canaveral, Florida Information

Cape Canaveral is a city in Brevard County, Florida. The population was 9,912 at the 2010 United States Census.[1] It is part of the Palm Bay–Melbourne–Titusville Metropolitan Statistical Area.

As of the census of 2000, there were 8,829 people, 5,066 households, and 2,097 families residing in the city. The population density was 3,788.0 inhabitants per square mile (1,463.0/km²). There were 6,641 housing units at an average density of 2,849.3 per square mile (1,100.5/km²). The racial makeup of the city was 94.68% White, 1.43% African American, 0.32% Native American, 1.70% Asian, 0.06% Pacific Islander, 0.42% from other races, and 1.40% from two or more races. Out of all of which Hispanics or Latinos of constituted 3.48% of the population, regardless of race.

There were 5,066 households out of which 11.9% had children under the age of 18 living with them, 30.7% were married couples living together, 7.4% had a female householder with no husband present, and 58.6% were non-families. 47.1% of all households were made up of individuals and 13.8% had someone living alone who was 65 years of age or older. The average household size was 1.74 and the average family size was 2.41.

In the city the population was spread out with 11.3% under the age of 18, 6.4% from 18 to 24, 30.4% from 25 to 44, 28.8% from 45 to 64, and 23.1% who were 65 years of age or older. The median age was 46 years. For every 100 females there were 109.1 males. For every 100 females age 18 and over, there were 107.7 males.

The median income for a household in the city was $30,858, and the median income for a family was $43,109. Males had a median income of $33,571 versus $22,423 for females. The per capita income for the city was $23,537. About 9.2% of families and 11.6% of the population were below the poverty line, including 28.7% of those under age 18 and 7.1% of those age 65 or over.

References and more area information on Wikipedia here >>

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